prove that if p and q are primes >2, then p+q is composite?

Answer 1

The simple explanation is that all prime numbers > 2 are odd. Adding 2 odd numbers will always get you an even number which is always conposite because it will be divisible by 2

Answer 2

Since p and q are primes > 2. Both of these must be odd numbers so their sum (p + q) will be an even number divisible by 2 i.e. it is composite.

Answer 3

Any prime > 2, being odd, can be represented as (2n + 1).
Let n1 = (2n + 1) and n2 = (2m + 1).
then
n1 + n2 = 2m + 2n + 2 = 2(m + n + 1),
which, of course, is divisible by 2

Answer 4

All primes over 2 are odd. An odd+ an odd is always even.