Help please?

Question

3√2x * 3√4x^2y^2 * 3√2y4
I don't understand this. The 3 are all cubic square root, help with this will be very much appreciated.
Thank you, in advance.

Answer 1

cube√2x * cube√4x^2y^2 * cube√2y^4

= cube√ (2x)(4x^2y^2)(2y^4)

= cube√ [(2x*4x^2y^2*2y^4)] Multiply together under √

= cube√ [(8x^3*2y^6) I'm keeping 2 in 2y^6 by itself since it won't be able to come out from under the cube root...

= 2x*y^2 cube√2

= 2xy^2 cube√2

:) Hope that helps.

Answer 2

First we need to know what you mean by cubic square root.
Do you mean cube root (x^2) or (square root (x))^3, or perhaps just the cube root of x. I'm going to assume that you mean the the symbol √ means cube root instead of square root. If this is true then we can rewrite your expression as
27√(2*8x^3y^6)
= 27*2xy^2*3√2
= 54xy^2√2, where √2 means cuberoot of 2

Answer 3

I assume you mean the cube [third] root.

1]. Multiply together all the numbers under the root signs.NOT

the powers, just the term quotients: 2x4x2x2 = 32.

2] Simplify the powers; x.x^2 = x^3, and y^2.y^4 = y^6, so the

sum now becomes: cube root of{32x^3y^6}: now, 32 = 8x4

and the cube root of 8 is 2. we cannot easily find the cube

root of 4, so we leave it as the cube root of 4. The cube root

of x^3y^6 is xy^2, so the answer is:

2xy^2cube Root4.

Answer 4

multiply everything under the cube root:

cbrt(2x * 4x^2y^2 * 2y^4)
cbrt(16x^3y^6)
2xy^2 cbrt(2)