If V = V1+V2, is necessarily greater than V1 and/or V2?

Answer 1

no. if for example v1 and v2 are negative, then v will be less than both.

Answer 2

No, not if one or both of the addends are negative. If V1 = -5 and V2 = -6, then V = V1 + V2 = (-5) + (-6) = -11, so V < V1 and V< V2. However, if V1 > 0 and V2 > 0, then V > V1 and V > V2.

Answer 3

What the heck is the question?

V has to be greater than at least one of the numbers.

V1 can be greater than V, which means V2 would have to be negative. If V2 is negative than V is greater than V2.

If V=V1 + V2
V - V1 = V2, If V1 > V, then V2 is negative, which means V > V2 as V
V - V2 = V1, If V2 < V, V1 can be either < or > V...how? Well if V2 & V are positive, V1 would be < V. If V2 is negative and V is positive, it would be positive minus a negative, which would be positive + positive which would mean V1 > V.

Answer 4

No. Consider that these are vectors. Suppose that V1 is 5 North and V2 is 4 South. The V is 1 North.

Answer 5

Are we talking about vectors or scalars here? With vectors, direction would matter as well as magnitude. If we are talking about scalars, V is not necessarily greater than V1 and/or V2. If both are negative, V is less than both V1 and V2. If we are talking vectors, there is a directional dependence so this statement is not necessarily true.

Answer 6

no unless you restrict V1 and V2 to be >= 0. Now it is true that the distance of V is > than the distance of V1 and/or V2

Answer 7

v=+ or v=- either v1 or v2
so 50 %?

Answer 8

The same question shows up again

Answer 9

Is what necessarily greater?

Answer 10

orientation is relevant