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3 answers

1) HBr(aq) --> H+(aq) + Br-(aq)
2) HF(aq) --> H+(aq) + F-(aq)

ref: http://en.wikipedia.org/wiki/Hydrofluoric_acid

3) Sr(s)
4) AgNO3(aq) --> Ag+(aq) + NO3-(aq)
5) Ag2SO4(aq) --> 2Ag+(aq) + SO4-2(aq)

ref: http://en.wikipedia.org/wiki/Silver_sulfate

2007-07-19 06:52:59 · answer #1 · answered by Dr Dave P 7 · 0 1

Both of the above answerers have some correct responses, but:
1. HF is a weak acid, so it is best to write HF(aq) as the majority product
2. NH4OH does not exist in any great concentration, because NH3 is a very weak alkali. It is better to write NH3(aq) as the majority product.
3. Sr is a very reactive metal, and it is impossible for it to remain in solution as the metal. The species in solution would be Sr2+(aq).

2007-07-19 08:24:40 · answer #2 · answered by Gervald F 7 · 0 1

H+(aq) + Br-(aq)
HF(aq) does not dissassociate
Sr(s)
NH4+(aq) + OH-(aq)
Ag+(aq) + NO3-(aq)
Either Ag2SO4(s) or 2Ag+(aq) + SO4 2-(aq) I don't have a chemistry book handy to check if the silver sulfate is soluble or not in water, but there should be a chart in the book

2007-07-19 06:39:49 · answer #3 · answered by three_from_beyond_the_arc 2 · 0 1

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