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how do you do these??

1.(1/2){ln (x^2) - ln y^4}
2.ln c - 2ln d

2007-07-19 05:51:40 · 3 answers · asked by lushay 2 in Science & Mathematics Mathematics

3 answers

1. 1/2 (2 ln x - 4 ln) [Using the Laws of logarithm]
= ln x - 2ln y [Opening the brackets]
= ln x - ln y^2
= ln (x/y^2)

2. ln c - ln d^2
= ln (c/d^2)


You may look for Laws of Logarithm on http://en.wikipedia.org/wiki/Logarithmic_identities

Hope this helps.

your_guide123@yahoo.com

2007-07-19 05:56:27 · answer #1 · answered by Prashant 6 · 1 0

1. ln (x/y^4)
2. ln (c/d^2)

2007-07-19 05:55:10 · answer #2 · answered by Andrew 4 · 0 0

1/2*ln(x^2) - ln(y^4) = 1/2*2*ln(x) - 4ln(y) = ln(x)-4ln(y) = ln(x/y^4)

ln c -2 ln d = ln(c/d^2)

2007-07-19 05:55:46 · answer #3 · answered by nyphdinmd 7 · 0 0

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