obtain its velocity & accleration at t = 2 sec
2007-07-19 03:35:39 · 3 answers · asked by baba bala krishnan 1 in Science & Mathematics ➔ Physics
take the derivative for the velocity
x' or v=8+14t
at t+2 the velocity is 36
take the derivative of the velocity to get the acceleration
x" or a=14
it is constantly accelerating at 14 time it irrelevant because there is no "t" in the equation for accceleration
2007-07-19 03:42:10 · answer #1 · answered by Kris Z 4 · 0⤊ 0⤋
x = 7t^2 + 8t + 3 is the expression for displacement.
Velocity is the first time derivative of displacement. v = x' = 14t + 8. At t = 2, v = 14*2 + 8 = 36
Acceleration is the second time derivative of displacement, making it the first time derivative of velocity. a = x'' = v' = 14 for any value of t.
2007-07-19 10:38:22 · answer #2 · answered by DavidK93 7 · 0⤊ 1⤋
x=3+8t+7t^2
v(t)=dx/dt=14t+8
a=dv/dt=14-constant
At t=2s,
v=14x2+8=36m/s, if x is in meters
and a=14m/s^2. ANS.
2007-07-19 10:42:59 · answer #3 · answered by Anonymous · 0⤊ 0⤋