A) (y3 – 3y)(y + 5) C) y(y2 – 5)(y + 3)
B) y(y2 – 3)(y + 5) D) (y3 – 5y)(y + 3)
2007-07-19 03:06:04 · 4 answers · asked by Sundance1 1 in Education & Reference ➔ Homework Help
Factor by grouping:
(y^4 - 5y^2) + (3y^3 - 15y)
Factor each group's common factor out:
y^2(y^2-5) + 3y(y^2 - 5)
Now y^2 - 5 is a common factor, so it comes out, leaving you with:
(y^2 - 5)(y^2 + 3y)
Taking y out of the second group, you get
y(y^2 - 5)(y+3), which is choice C.
2007-07-19 04:22:00 · answer #1 · answered by jenh42002 7 · 0⤊ 0⤋
15y+19y+6 = 34y + 6 = 2(17y + 3) can not be factor anymore
2016-05-17 09:22:47 · answer #2 · answered by ? 3 · 0⤊ 0⤋
Whenever you have a multiple choice question...let the variable be a number stay away from 1...and plug it into your problem...you should get a numerical answer...then plug the same value for the variable into your answer choices and see which one gives you the same answer is the correct choice...you can find the answer this way...i will not give you the answer
2007-07-19 04:29:34 · answer #3 · answered by jessju18 2 · 0⤊ 0⤋
C is the one that works.
2007-07-19 03:12:05 · answer #4 · answered by 16oeoj 4 · 0⤊ 0⤋