For a material object, no. How much less depends on several factors. The answer lies in recognizing that MC^2 is a value of mass times acceleration times distance. Therefore C^2 is, in part, representing a maximum acceleration which can be achieved due to the force exerted by a particle. It is known what the maximum acceleration can be. An object can only be accelerated to the approximate speed of light. The real question to be answered is: ‘What is the minimum theoretical distance over which this maximum acceleration can be achieved?’ That distance is the length of one photon. The term C^2 can be understood as the maximum acceleration times the length of a photon. It is really dVmax/dtc^2 times dxc where dxc is the length of a photon. The maximum acceleration is from zero to the speed of light. Therefore, it can also be written as C/dtc times dxc. The value of dtc is not arbitrary. It is the period of time it takes for a photon to move passed a given point. It is a fundamental constant. It can be seen that dxc/dtc is equal to C. So the maximum acceleration times the shortest possible distance is C^2..
2007-07-25 03:08:59
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answer #1
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answered by ? 6
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Certainly. The theory of relativity does not limit the rate of acceleration only the maximum velocity. However the energy needed is enormous. For instance, in a particle accelerator if you used say an alpha particle and accelerate it to a very high velocity and it collides with another particle, let's say a proton the proton will accelerate very rapidly.
2007-07-18 23:08:16
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answer #2
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answered by Charles C 7
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The speed of Light is the maximum velocity that any physical body can have and still remain in this Universe of 4 dimensions. When any object approaches the speed of light, it's dimensions in the direction of that acceleration approaches zero, as does it's "velocity" in the direction of Time. This is probably why subatomic particles such as the photon have such a strange duality.
2007-07-26 09:40:34
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answer #3
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answered by Dale C 1
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C = the "speed" of light...not the "acceleration"
Earth's gravity is equal to 9.8 m/sec^2
In order to have an acceleration of 299,792,452 m/sec^2 (just shy of the speed of light per sec in just one second), you'd have to be able to push something hard enough for it to go the speed of light in just over one second.
This is not possible due to m' = m/(sqrt 1-(v^2C^2). In other words, as your velocity became close to the speed of light, V^2/C^2 would close in on "1"... 1 - 1 = 0...the sqrt of 0 is "0"...so you'd have m/0...or "infiniti"...meaning it would take an infinite amount of energy to accelerate you to the speed of light because your mass had approached infiniti as you got nearer...so you'd never get there, and therefore never be able to be accelerated at the rate you specified.
Any object qualifying as a "body" would be too large to be accelerated to this rate, even for the smallest fraction of time, because the rate is unreachable for anything considered to be "matter" (a requirement for something to be a body).
2007-07-25 17:15:42
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answer #4
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answered by Kevin S 7
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It is possible but highly unlikely, at that velocity you are approaching the speed of light, the amount of energy required to go faster is just not available.
2007-07-23 12:44:17
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answer #5
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answered by johnandeileen2000 7
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remember according to the theory of relativity there is nothing in this universe which can travel at speed greater than that of light.
thus maximum accelaration is (3x10^8)m/sec^2.
assuming speed of light is (3x10^8)m/sec.
2.99...what you gave is approximately less than (3x10^8)m/sec so it is possible to have accelaration more than that but maximum is (3x10^8)m/sec.
2007-07-18 23:07:21
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answer #6
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answered by Someone 3
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