Determine the slope of theline perpendicular to the line
-5x-3y+8=0 Please explain
2007-07-18 21:03:24 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
3y = -5x + 8
y = -5/3x + 8/3
Slope is -5/3. The slope of the perpendicular is the negative inverse, i.e. 3/5.
2007-07-18 21:08:29 · answer #1 · answered by gebobs 6 · 1⤊ 0⤋
In order to find the slope of a perpendicular line you must first find the slope of the line you already have. The way I would do this is convert to slope-intercept form.
-5x-3y+8 = 0
-3y = 5x - 8
y = -(5/3)x + (8/3)
The slope of a line perpendicular is what I like to refer to as the "opposite reciprocal." That is, take the opposite sign and flip the numerator/denominator.
m = 3/5
2007-07-19 04:07:42 · answer #2 · answered by alwaysandnever 2 · 1⤊ 0⤋
3y = - 5x + 8
y = - 5/3 x + 8/3
slope of this line is - 5/3
slope of the perpendicular line is 3/5
m = 3/5
2007-07-19 08:05:36 · answer #3 · answered by CPUcate 6 · 0⤊ 0⤋