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I'm not too good with searching for specific things, especially dealing with data.

I have a math project to do, and my teacher wants us to find a real life "phenomena" that has increases and levels out. It should also resemble a square root function. I really have no clue where to start.

If this makes sense, please help! Thanks!

2007-07-18 19:13:18 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

Try working with the brightness of a light bulb and the distance at which it is observed.

If you turn on a light bulb and are 1 ft away from it then it may have a certain intensity at that point. But as you move further away from the source then the brightness fades. The distance you move is inversely related to the square root of the brightness you encounter. In other words if you move twice the distance away from the source you are down to 1/4 the brightness at your previous position.
Also try posing this question in the physics section you will get more answers.

2007-07-18 19:32:58 · answer #1 · answered by 037 G 6 · 0 0

By square root function I assume you mean:
y = sqrt(x)
So as x increases y increases then depreciates slowly. Let me write this in terms of calculus:
lim x->Positive infinity ( y -> a ), where a is a constant number
Now to find a real life example, lets say x is a variable representing time, so now as time approaches infinity or in short term increases, well not increases but passes, a variable y increases and levels out.
This is quite rare because most life functions involve e, or a cycle, hmmm.
My best example would be the amount of melted water of an ice cube.
An ice cube has a surface area: 6(s^2) where s is a side of the cube. The rate that it melts is dependent on the surface area, and as the cube melts the surface area decreases so the water increases in amount as the ice decreases but more slowly as it progresses. Try this with an ice cube, put it on the counter. Watch it melt, you should note that at first it melts quickly because more of the surface area is exposed to the air which is supposedly warmer heating up the ice and melting it to water. You should note that the water increases quickly at first, then less as time goes on but still increases until all the ice has melted into water which is the asymptote.
Hope that makes sense

2007-07-18 19:32:23 · answer #2 · answered by Anonymous · 0 0

i'm at the instant interior the comparable classification besides, yet for some reason I save getting blunders C3861: 'weirdSqaureRoot': identifier no longer got here upon. below is what I even have so a techniques. would any of you have an understand-how of the place I went incorrect? #include79abd8cf35895c56cc4d955c5355dbe #include7c5062c74d78a7ba9712f8906add22 utilising namespace std; double weirdSquareRoot(double variety) { return sqrt(variety); } int significant() { double num, absNum; do { cout << "enter a variety (a double): "; cin >> num; absNum = abs(num); if (absNum > 0) { cout << "The sq. root is " << weirdSquareRoot(absNum) << endl; } if (absNum < 0) { double absNum = abs(num); cout << "The sq. root is: -" << weirdSqaureRoot(absNum) << endl; } } collectively as (num != 0); }

2016-11-09 20:58:45 · answer #3 · answered by Anonymous · 0 0

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