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1. NaOH + KClO3 -->
2. NaOH + NaBr -->
3. NaOH + NH4Cl -->
4. NaOH + Na2SO4 -->
5. NaOH + KIO3 -->
6. NaOH + Na2S -->

Help Please!

2007-07-18 14:58:57 · 2 answers · asked by cbrice9 1 in Science & Mathematics Chemistry

2 answers

1. Doubt if anything happens.
2. Ditto
3. Products are NaCl and NH4OH
4. Nothing happens
5. Nothing happens
6. Nothing happens.

Just because you write down two compounds doesn't mean you will have a reaction. You have to ask yourself "what reaction will happen". Double displacement- what is being displaced?
Acid-base - are the products weaker acids/bases?
RedOx- What can be oxidized and what can be reduced.

2007-07-18 15:10:34 · answer #1 · answered by cattbarf 7 · 0 0

KClO3is a strong oxidising agent and is a salt of strong acid and strong base so no acid base reaction can take place(as KClO3 is neutral). Therefore no chance of any reaction.Sameisthe case NaOH &NaBr.Infact in presence of heatBr2 reacts with NaOH to form NaBrO3 &NaBr.with NaOH andKI03&alsoNaOH and Na2SO4 no reaction occurs.with NaOH andNH4Cl NH3 gets formed.the equation is
NH4Cl+ NaOH=NaCl+H2O+NH3.This is actually an acid base reaction where NH4Cl is the acid.The ionic equation would be
NH4Cl+OH-=NH3+Cl-+H2O
for the last reaction probably gives polysulphides.

2007-07-18 17:11:07 · answer #2 · answered by Anonymous · 0 0

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