What's the formula in getting distance?

Question

I only want to know what's the formula for getting distance.

Answer 1

Distance between two points?

In two dimensions:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2)

In three dimensions:
d = sqrt((x2 - x1)^2 + (y2 - y1)^2 + (z2 - z1)^2)

Distance given a constant velocity over a given time?

d = v * t

Distance given a constant acceleration over a given time?

d = 1/2 * a * t^2 + v0*t

Distance given a surveyor's kit that gives you an angle of ascension and a height to the target?

d = h / tan(theta)

Answer 2

Distance = speed x time

Answer 3

D=R(T)
Distance = Rate multiplied by Time

Hope that helps.

Answer 4

S = r t . . . .S = distance . . r = rate . . . t = time

S = Vo t + 1/2 g t^2 . . . .projectile formula . . . vertical motion
. . . . . . . . Vo = initial velocity .. t= time . .. g = gravity

S = V^2 / (2 g) . . . . for vertical motion

Answer 5

rate times time = distance [d = rt]
The distance between two points in a coordinate system is
d = sqrt(x2-x1)^2 + (y2-y1)^2)

Answer 6

speed x time =distance

Answer 7

hi

falling body

h = h0 + V0 * t + 1/2 g * t^2

bye

Answer 8

what do you know? what are you given?

distance is in meters (m)
velocity is in meters per second (m/s)
acceleration is in meters per second squared (m/s^2)
dist = veloc x time, ie you're driving
dist = acceleration x time^2, ie you're falling, acceleration =9.81m/s^2