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given: 7[(7y/3)+10]=49
prove: y=-9/7

2007-07-18 12:05:40 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

7[(7y/3)+10]=49 [Given]
7y/3+10=7[ Division Axiom]
7y/3=-3 [Subtraction Axiom]
7y = -9 [Multiplication Axiom]
y = -9/7 [Division Axiom]

Q.E.D

2007-07-18 12:22:19 · answer #1 · answered by ironduke8159 7 · 0 0

7[(7y/3)+10]=49

division
7y/3 + 10 = 7

subtraction
7y/3 = -3

multiplication
7y = -9

division
y = -9/7

2007-07-18 19:09:28 · answer #2 · answered by      7 · 1 0

7[ (7y/3) + 10 ] = 49
7[ (7y + 30 ) /3 ] = 49
[ (7y + 30 ) ] = 21
7y = - 9
y = - 9/7

2007-07-18 19:11:01 · answer #3 · answered by CPUcate 6 · 1 0

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