The distributive property is the standard way to do it: a(b + c) = ab + ac.
Apply it once to get rid of the first parentheses:
(√[6] + 2√[2])(4√[6] – 3√[2]) =
√[6](4√[6] – 3√[2]) + 2√[2](4√[6] – 3√[2])
And then twice more, once on each of the resulting terms:
√[6](4√[6] – 3√[2]) =
√[6](4√[6] + (√[6])(–3√[2])
2√[2](4√[6] – 3√[2]) =
2√[2](4√[6]) + 2√[2](–3√[2])
Then add all that up.
As a shorthand, you can use FOIL when you are multiplying two expressions with two terms each. It stands for the sum of the products of the:
* [F]irst terms (√[6] * 4√[6]) of each sum
* [O]uter terms (√[6] * – 3√[2]) furthest apart
* [I]nner terms (2√[2] * 4√[6]) closest together
* [L]ast terms (2√[2] * – 3√[2]) of each sum
(a + b)(c + d) = ac + ad + bc + bd
In this case your answer is:
√[6](4√[6] + (√[6])(–3√[2]) + 2√[2](4√[6]) + 2√[2](–3√[2])
... which simplifies to:
4*6 - 6√3 + 16√3 - 6*2
24 - 12 + 16√3 - 6√3
12 + 10√3
2007-07-18 11:37:36
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answer #1
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answered by McFate 7
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(â[6] + 2â[2])(4â[6] – 3â[2])
=4â(6*6) -3â(6*2) +2*4*â(2*6) -2*3â(2*2)
=24 - 3â(4*3) +8â(4*3) -6*2
=24 - 6â3 +16â3 -12
= 12 +10â3
2007-07-18 18:49:24
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answer #2
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answered by ironduke8159 7
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use foil
F 4 sqtr (36) O -3 sqrt(12) I 8 sqrt (12) -6 sqrt (4)
and simplify
24 - 6 sqrt (3) + 16 sqrt (3) -12
combine like terms
12 + 10 sqrt (3)
2007-07-18 18:34:36
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answer #3
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answered by gfulton57 4
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(sqrt[6]+2 sqrt(2(4sqrt[6])=3sqrt[2])
=sqrt[6]x4 sqrt[6]]-2sqrt{2]x3sqrt[2]}-sqrt[6]x3sqrt[2]+2sqrt[2]x4sqrt[6]
=24-12-6sqrt[3]+16xsqrt[3]
=12+10xsqrt[3].ANS.
2007-07-18 18:51:22
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answer #4
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answered by Anonymous
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your face. :-P
2007-07-18 18:34:43
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answer #5
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answered by <3 aili-marie <3 3
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