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I'm supposed to derive this: y = e^(-8x) cos(3x)

I got -3sin(exp(x))exp(-8x) -8cos(3x)exp(-8x)

but its not right..any help would be appreciated.

2007-07-18 10:46:42 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

y = e^(-8x) cos(3x)
y' = e^{-8x} (-sin(3x) 3) + (-8) e^{-8x} cos(3x)

2007-07-22 09:00:29 · answer #1 · answered by Anonymous · 1 0

The verb for taking a derivative is not "to derive". It is "to differentiate".

When you differentiate e^(-8*x)*cos(3*x) with respect to x, you get:

-e^(-8*x) * (8*cos(3*x) + 3*sin(3*x))

2007-07-18 17:52:50 · answer #2 · answered by lithiumdeuteride 7 · 0 0

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