Mg(OH)2 (s) = Mg^2 (aq) + 2 OH^- (aq)
Is this reaction endothermic or exothermic and why
2007-07-18 10:26:02 · 0 answers · asked by D 1 in Science & Mathematics ➔ Chemistry
This reaction is exothermic. EDTA is a chelating agent and it chelates with the magnesium ion and it will remove it from the soution. The reaction will release energy because the solubility product for the formation of the complex of magnesium and EDTA is less than that of Mg(OH)2 .
2007-07-18 12:15:33 · answer #1 · answered by scott k 4 · 0⤊ 0⤋
The equilibrium shifts to the right, because EDTA sequesters (binds) Mg2+, thus taking it "out" of the solution. This assumes that the binding constant for Mg(EDTA) is stronger than the solubility product of Mg(OH)2. The reaction is exothermic, because the energy difference is greater toward the EDTA chelate.
2007-07-18 11:36:56 · answer #2 · answered by steve_geo1 7 · 3⤊ 0⤋
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Which way should the following equilibrium shift when Na2EDTA is added, and why?
Mg(OH)2 (s) = Mg^2 (aq) + 2 OH^- (aq)
Is this reaction endothermic or exothermic and why
2015-08-12 06:35:04 · answer #3 · answered by Tifany 1 · 0⤊ 0⤋
Na2 Edta
2016-10-16 07:20:15 · answer #4 · answered by Anonymous · 0⤊ 0⤋
it will be shifted to the right, since the OH produced will react with the HCl, thus requiring more Mg(OH)2 to dissolve.
2016-03-14 19:32:17 · answer #5 · answered by Anonymous · 0⤊ 0⤋