100e^(2x) = 600
e^(2x) = 6
2 x = ln 6
x = ln 6 / 2
2007-07-18 08:53:03
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answer #1
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answered by oregfiu 7
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100e^(2x) = 600
ln(100e^(2x)) = ln(600)
The left side is
ln(100) + 2x
So now you have
ln(100) + 2x = ln(600)
Add -ln(100) to both sides
2x =ln(600) - ln(100) = ln(600/100) = ln(6)
Multiply both sides by 1/2
x = (1/2)ln(6) = ln(â6)
2007-07-18 16:04:18
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answer #2
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answered by gugliamo00 7
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100e^(2x) = 600
100e^(2x)/100 = 600/100
e^(2x) = 6
ln e^(2x) = ln 6
2x = ln 6
x = (ln 6)/2
x = 0.8959
2007-07-18 15:55:27
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answer #3
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answered by sdb deacon 6
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100e^(2x) = 600
e^(2x) = 6
2x = ln 6
x = 2(ln 6)
so........x = 0.8959
2007-07-18 16:00:18
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answer #4
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answered by Just.Dako. 2
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e^2x = 6, and take ln of each side:
2x = ln(6)
x = .5*ln(6) = .896 (rounded)
2007-07-18 15:54:02
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answer #5
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answered by John V 6
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Sit next to the smart kid.
2007-07-18 15:52:07
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answer #6
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answered by MensaMan 5
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punch yourself in the face and do your own home work.
2007-07-18 15:51:36
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answer #7
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answered by Anonymous
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