We came up with an answer, but the teacher says we are wrong, but he hasn't got an answer for us yet
He said he will give us an answer tomorrow...
The question is...
Write a formula for the charge, C, to send telegrams at a cost of 75 cents for the first 10 words and 5 cents each for N additional words.
I say its "c = .75 + .05n"
And he is saying that what if the telegram is 8 words or has 14 words total
Then it would be .75 + .05(14)
But we are telling him it would be .75 for the first ten and then .05(4) for the four additional words
But he is saying that it is not clear enough
Can somebody please find the correct answer or explain a way for my answer to be correct?
Thanks
2007-07-18 05:38:31 · 10 answers · asked by Zae Boogie 2 in Science & Mathematics ➔ Mathematics
It seems obvious to be that the equations for this problem are:
if total words is less then or equal to 10, c= 75 cents
however if total words > 10
c= .75 +.05n
75 cents is the base charge and there is an additional charge for longer messages. I don't really understand how there is much of a dispute. This is a piecewise linear function word problem.
2007-07-18 05:49:57 · answer #1 · answered by palm 2 · 0⤊ 0⤋
How about C = .75 + .05N, where N is the number of words above 10. N would be zero if the message were 10 words or fewer, and so C = .75. Otherwise the 5 cent charge only applies to the excess aboce 10.
2007-07-18 13:09:57 · answer #2 · answered by John V 6 · 0⤊ 0⤋
C=.75+.05(n)
2007-07-18 13:30:40 · answer #3 · answered by MissTT 3 · 0⤊ 1⤋
You need a piecemeal equation:
if n<=10 C=.75
if n>10 C=.75+.05(n-10)
2007-07-18 12:44:06 · answer #4 · answered by Spider 2 · 3⤊ 0⤋
c=.75+.05(w-10) where w >10
try that, the problem is that he is being imprecise in his wording and it would be very difficult to form an equation where if the number of words is under 10 the modifier cancelled out.
2007-07-18 12:47:31 · answer #5 · answered by waytoosteve 3 · 0⤊ 0⤋
It is C= .75 + .05(n-10)
The first 10 words are included in the $0.75.
n = total words, so 11 words would be .75 + .05(11-10) or C = .75 + .05(1) or C = .80
2007-07-18 12:42:32 · answer #6 · answered by Anonymous · 0⤊ 3⤋
I think yours is OK IF you add the following condition:
"Where n is the number of words in the message above 10. If the number of words is less than or equal to 10, then n=0."
2007-07-18 12:47:40 · answer #7 · answered by hcbiochem 7 · 0⤊ 0⤋
its a complex function
if the # of words=< 10 than C=.75
if the # of words > 10 than C= .75+.05N
you cant state this with a single equation/function
2007-07-18 12:45:00 · answer #8 · answered by mete 5 · 0⤊ 3⤋
The 0.75 is a flat charge rather than a per-word charge right?
Then you could write it like this:
C = 0.75 + 0.05*{n - 10}
where {x} = 0 if x<0
and {x} = x if x>0
2007-07-18 12:57:49 · answer #9 · answered by Dr D 7 · 0⤊ 0⤋
cost = .75 + .025 ( n-10+|10-n| )
|x| is absolute value of x
2007-07-18 13:21:00 · answer #10 · answered by Anonymous · 0⤊ 1⤋