An airbag needs 15 mols of nitrogen gas, so how many grams of sodium azide should be installed in the airbag?

Question

2 NaN3 -> 2Na + 3N2

Answer 1

2NaN3 ---> 2Na +3N2

By looking at the balanced equation, we can see that the ratio of moles of sodium azide to nitrogen is 2:3

So, if we need 15 moles of N2 gas, we would need 10 moles of sodium azide.

Now let us find the molecular mass of sodium azide.

Mr (NaN3) = 23+3(14)=65

1 mole of sodium azide weighs 65g.

Hence,

10 moles of sodium azide weighs 10x65 = 650 grams. (Ans)

Hope this helps =)

Answer 2

So first make a balanced equation 2 NaN3 <-----> 2 Na+ + 3 N2(g) So for each 2 moles of sodium azide, you're making 3 moles of Nitrogen gasoline. Now discover what number moles you have. Nitrogen is 14g/mol and Sodium is 23g/mol meaning that sodium azide is 65g/mol and nitrogen gasoline is 28g/mol So what number moles are in sodium azide? 429g/ 65g/mol = 6.6mol of sodium azide so for each 2 moles of sodium azide you get 3 moles of nitrogen gasoline. so 6.6mol X (3moles nitrogen gasoline/2mol of sodium azide) = 9.9mol now what number molecules are in 9.9moles? 9.9mol X 6.022X10^23 (avagadro's variety) = 5.96X10^24 molecules or 6.0 X 10^24 consequently, E is the respond

Answer 3

2NaN3 = 46 + 84 = 130g/mol. = 3 moles N2.
15mol x 130g/mol.
1,950grams NaN3 ÷ 3 = 650grams.

Answer 4

650 grams.