When 0.240 mol of HCOOH is dissolved in 0.916 L of water, proton transfer occurs.
HCOOH + H2O ↔ HCOO- + H3O+
The equilibrium concentration of H3O+ ions is 0.00674 M. Evaluate Keq.
2007-07-18 04:59:19 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Ka = [HCOOˉ][H3O+]/[HCOOH]
You are given [H3O+]
[HCOOˉ] = [H3O+] because they both come from the same source
[HCOOH] = (0.240/0.916) - 0.00674
Put all these figures into the first equation and you have your answer - it is not the one given in a previous answer
2007-07-18 12:25:21 · answer #1 · answered by Chemmunicator 5 · 0⤊ 0⤋
You've got to stop asking questions and actually do the work for yourself.
divide moles of HCOOH/liters of water to get your molarity of your reactants.
Then divide your product molarity (H3O+) / reactant molarity (HCOOH)
That will give you Keq
2007-07-18 12:05:17 · answer #2 · answered by misscarinne 4 · 0⤊ 1⤋
4.9 x 10^3
2007-07-18 12:18:40 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 1⤋