prove that x raised to the power 0 =1?

Answer 1

It's because x^a / x^a = 1
LHS = x^(a-a) = x^0 = RHS = 1

Answer 2

x^a/x^b = x^(a - b)
so x^a/x^a = 1 = x^(a -a) = x^0

Answer 3

x^4 / x = x^(4 - 1) = x³
x³ / x = x ^(3 - 1) = x²
x² / x = x^(2 - 1) = x^1
x / x = x^(1 - 1) = x^0
But x / x = 1
Thus x^0 = 1

Answer 4

I assume you`re familiar with the 2nd rule of indices,

p^c divided by p^d = p^c-d.

Consider p^7 divided by p^7, then by the second rule, this is

equal to p^0.

However, we know that any number divided by itself, say

17 divided by 17 = 1,so,. p^7 divided by p^7 = p^0 = 1

Hence any number raised to the power of zero is one.

Answer 5

x^6/x^6 = 1
and
x^6/x^6 = x^0

=> x^0 =1

Answer 6

given the formula:
(x^a) / (x^b) = x^(a-b)
and
C/C = 1 for any non-zero C.

Let C = x^a
then
C/C = (x^a) / (x^a)
1 = x^(a-a)
1 = x^0

Answer 7

If x not equal to zero, choose any m not equal to zero.

x^0 = x^(m-m) = (x^m)(x^-m) = (x^m)/(x^m) = 1

Answer 8

I just had college algebra. It sucked, I am sorry you are on your own on this one.