Calculate the force between an electron and proton?

Question

Of a Hydrogen atom. Please help.

Answer 1

The force is equal to (k_e)(q_1)(q_2) / r^2.

k_e is a constant, and sometimes it is written as 1 / (4*pi*e_0), where e_0 is the permittivity of free space. k_e = 8.988 x 10^9 N-m^2 / C^2.

q_1 and q_2 are the charges, and they are equal to each other; both are 1.602 x 10^-19 C. The proton has postiive charge and the electron has negative charge.

r^2 is the distance between them. There are different values for the radius of a hydrogen atom; have you been given one to use? If not, you should probably use the Bohr radius of 53 x 10^-12 m.

You now have all of the values needed to use the formula. Remember that the charges are dissimilar (one positive, one negative), so the force will be attractive.

Answer 2

theelectrostatic forceF of attraction between the electron and proton of the hydrogen atomis given by :

F=(1/4pi e(0)) q^2/r^2.
where q is the magnitude of the charge on the electon or the protonand r is the distance between the two.

Answer 3

a million. Use Coulomb's regulation F = Q1*Q2 / (4*Pi*epsilson*r^2) = 2.3 x 10^-8 N the fees are opposite, hence the tension is eye-catching. 2. Use Newton's regulation of Gravitation F = G*M1*M2/r^2 = a million x10^-40 seven N Gravitational tension is often eye-catching. right here the gravitational tension is below the electrostatic tension.