x: 0 1 2 3 4 5
y: 0 1 3 7 15 31
I need a formula that works for these values please!!?
2007-07-17 23:46:03 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
The successive differences in the values are 1 2 4 8 16 32, i.e., powers of 2. Also, the y values are one less than the corresponding power of 2 produces by the x value.
So y = 2^x - 1
2007-07-17 23:55:01 · answer #1 · answered by John V 6 · 0⤊ 0⤋
y=(2^x) -1
2007-07-18 06:52:22 · answer #2 · answered by charliefromwashington 3 · 1⤊ 0⤋
y = 2^x - 1
when x = 0, y = 2^0 -1 =0
x = 1, y = 2^1 -1 =1
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2007-07-18 06:52:25 · answer #3 · answered by me_poori 2 · 1⤊ 0⤋
y=2x^2-1
2007-07-18 06:54:12 · answer #4 · answered by koooooooooooool 2 · 0⤊ 0⤋
x is an arithmetical progression and y is a geometric progression. So, work out the formula for y.
2007-07-18 06:52:18 · answer #5 · answered by Swamy 7 · 0⤊ 1⤋