How do you do this problem ?

Question

Factor the trinomial by grouping.
6y2 - 13y + 6

(6y + 3)(y + 2)
(2y + 3)(3y + 2)
(2y - 3)(3y - 2)
prime

Answer 1

It's the 3rd of your possibilities, (2y - 3)(3y - 2).

["FOILing" the latter gives 6y^2 - 4y - 9y + 6 = 6y^2 - 13y +6, i.e. the original trinomial.]

I confess that I simply don't understand the people who enthusiastically embrace or promote "grouping." "Grouping" was never taught when I learned my algebra. As far as I can tell from examples I've seen in Yahoo Answers it's only straightforward when the answer is almost obvious anyway.

If there is the possiblity of multiple sets of factors, you basically have to know which ones are the right combination in order to "group" in the desirable way.

No fancy name was ever given for the "method" we were taught, but it was basically "Consider what possible pairs of factors there might be, and then see what will do the job."

That seems to work quite well in practice!

Live long and prosper.

Answer 2

6y^2 - 13y + 6 cannot be factored into any of the answers given.

y = 1, expression = -1

y = 2, expression = + 4

y = 3, expression = 21

So, it is not a prime either.

Answer 3

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