2007-07-17 18:36:20 · 8 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Does anybody know the imaginary solutions?
2007-07-17 18:47:30 · update #1
x^2 +12x = -45
x^2 +12x + 36 = -45 + 36
(x+6)^2 = -9
x+6 = +/-3i
x = -6 +/- 3i
2007-07-17 18:46:19 · answer #1 · answered by bourqueno77 4 · 1⤊ 0⤋
You can do this!
x^2 +12x +45 = 0
(x+___)(x+___)=0
There are no two integers that muliply to equal 45 and add to equal 12.
If you are in pre-algebra, there is no solution.
If the 45 was mistyped and is actually positive, then the first posters solution would be correct.
If you have been introducd to the Quadratic Formula, then you can solve this by plugging in a=1, b=12, c=45.
2007-07-18 01:48:44 · answer #2 · answered by bedbye 6 · 0⤊ 1⤋
you can change it to X^2 +12X + 45 =0, and then factor it out (X+15)(X-3)=0, so the answers are -15 and 3
2007-07-18 02:36:41 · answer #3 · answered by Alexander Vincentius Yunus 3 · 0⤊ 0⤋
x² + 12 + 45 = 0
(x + 15) (x - 3) = 0
x = - 15 , x = 3 (Real solutions)
2007-07-19 06:34:26 · answer #4 · answered by Como 7 · 0⤊ 0⤋
If you move the -45 back over you have x^2+12x+45. Then you factor. (x+15)(x-3). Using foil you get the above equation, if you need to check your answer.
Just in case: FOIL is multiply front, outside, inside, and last.
2007-07-18 01:44:00 · answer #5 · answered by macksgurl_04 2 · 1⤊ 1⤋
it has no solutions.u just solve the Delta prime(=36-45) and see its negative so it has no real(R) solutions.
2007-07-18 01:43:50 · answer #6 · answered by bioneoface 1 · 1⤊ 0⤋
-6+3i, -6-3i
2007-07-18 01:47:17 · answer #7 · answered by arya 2 · 0⤊ 1⤋
factor it out;
factors are (x-3)(x+15)=0
x=3,-15
2007-07-18 01:40:09 · answer #8 · answered by Mr. Engr. 3 · 0⤊ 3⤋