How do you find the height for this word problem?

Question

a baseball is thrown straight up with an initial velocity of 112 ft per second from a height of 5 feet. How high is the ball after 3 seconds?
Using: h = -16.1t^2 + Vot

Answer 1

t= 3 secs.
Vo=112 ft/sec

h = -16.1t^2 + Vot
=-16.1*3*3 + 112*3
=-144.9+336
=191.1 ft.
This will be the height attained by ball after 3 secs. from the place it was thrown. So, the total height will be
191.1+5
=196.1 ft.

Answer 2

Just substitute 3 for t (time) and 112 for V0 (initial velocity) in to the equation, and add 5, since that is the starting height.

So h = -16.1*9 +112*3 +5
= -144.9 + 336 +5
which is 196.1 feet.

which seems very high, but then again the initial velocity is very high.....
.

Answer 3

Don't you have any concept of what the equation means? If you did, you wouldn't ask this (a variant on one about the rock in the well). Here, Vo =112, and you add 5 ft to the answer.

Answer 4

h = (-16.1(3^2) +112) +5