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It is college Algebra and I need someone to help me big time, I am not good at this and do not understand factoring.

2007-07-17 17:02:19 · 8 answers · asked by sunshine 1 in Science & Mathematics Mathematics

8 answers

If in your question you meant (x^5)(y^3)-9(x^4)(y^2)+20(x^3)y....
then you can see that all three terms have an (x^3)y. If you factor it out, your expression now is [(x^3)y] [(x^2)(y^2) - 9xy + 20]. (To verify, multiply (x^3)y with the other 3 terms- you should get your original expression. ) This can factor further into [(x^3)y](xy-4)(xy-5). Hope this helps

2007-07-17 17:19:07 · answer #1 · answered by readerno14 2 · 0 0

Reading question as
x^5y³ - 9x^4 y² + 20 x³ y:-
x³ y (x² y² - 9 x y + 20)
x³ y (xy - 5) (xy - 4)

2007-07-17 19:52:51 · answer #2 · answered by Como 7 · 0 0

First do this x5y3 -9x4y2+20x3y is divisible by x3y which gives you x2y2-9xy+20 factoring each side you get (xy-5)(xy-4) so factored out it is x3y(xy-5)(xy-4).

2007-07-17 17:21:01 · answer #3 · answered by Emissary 6 · 0 0

I believe you must use the substitution method. I am in 10th grade and have the same problems.

2007-07-17 17:05:24 · answer #4 · answered by Oyabun Shinobi Kai 2 · 0 1

x^5y^3 – 9x^4y^2 + 20x^3y
x^3y(x²y² - 9xy + 20)
x^3y(xy-4)(xy-5)

2007-07-17 17:14:28 · answer #5 · answered by bourqueno77 4 · 0 0

Umm ur gonna have to clear it up when u mean x5y3 do u mean (x^5)(y^3)?

2007-07-17 17:05:40 · answer #6 · answered by SCgoon341 1 · 0 1

the answer is 3x(9=3)

2007-07-17 17:05:11 · answer #7 · answered by sirblackie 4 · 0 1

IDK? = 24x4y2

2007-07-17 17:13:29 · answer #8 · answered by dm 3 · 0 1

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