help with science math problem !?

0 ⤊

help with science math problem !?

i need to know how to calculate- the power in kilowatts required to pull a car up a ramp if the amount of work is 250kj over a period of 45s ?????????????????? pls help!

2007-07-17 14:25:06 · 3 answers · asked by malaine 2 in Science & Mathematics ➔ Mathematics

3 answers

Power = Work/time

P = 250 kJ/45 s = 4.56 kW (because energy was in kJ)

2007-07-17 14:29:01 · answer #1 · answered by nyphdinmd 7 · 0⤊ 0⤋

power in w = power in j / s
x = 250kj / 45s
x = 5.56 kw

2007-07-17 21:29:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋

Power = work / time

250 Kj = 250,000J

power = 250,000 / 45
power = 5555.56 watts = 5.6 kW

2007-07-17 21:29:51 · answer #3 · answered by 7 · 0⤊ 0⤋