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For the reaction 2NO2(g) ì N2O4(g) at 325 K equilibrium is established when [N2O4] = 0.020M and [NO2] = 1.08 ´ 10- 2M. What is the equilibrium constant for this reaction?

5.8 x 10^-3
2.9 x 10^-1
5.4 x 10^-1
1.7 x 10^2

2007-07-17 07:38:28 · 2 answers · asked by Anonymous in Science & Mathematics Chemistry

2 answers

K = [N2O4]/[NO2]^2

K = 0.02/(1.08 x 10^-2)^-2

K = 1.7 x 10^2

2007-07-17 07:49:18 · answer #1 · answered by steve_geo1 7 · 0 0

171

2007-07-17 14:45:33 · answer #2 · answered by deflagrated 4 · 0 0

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