2007-07-17 06:59:18 · 6 answers · asked by jessica f 1 in Science & Mathematics ➔ Mathematics
Let us assume that B will be 4 times as old as A in x years
Hence by the problem
(68+x)=4(11+x)
or 68+x=44+4x
or,x-4x=44-68
or,-3x= -24
or x=8
Therefore in 8 years B will be 4 times as old as A
2007-07-17 07:05:45 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
Let x be the number of years needed to fulfill the condition in the question.
At this year, A = 11 and B=68. After x years, A will be 11+x years old and B will be 68+x years old. Also, after x years, B will be 4 times as old as A, hence, we can form an equation as follows:
68+x = 4(11+x)
68+x = 44+4x
4x-x = 68-44
3x=24
x=8
This means that in 8 years, the condition above will be fulfilled.
2007-07-17 07:07:39 · answer #2 · answered by HarpoonDragoon 3 · 0⤊ 0⤋
A = 11
B = 68
Let X be the time period.
B + X = 4(A + X)
68 + X = 44 + 4X
3X = 68 - 44
X = 8
In 8 years B will be 4A.
2007-07-17 07:04:31 · answer #3 · answered by Anonymous · 0⤊ 0⤋
4(11+x) = 68 + x
44 + 4x = 68 + x
3x = 24
x = 8
2007-07-17 07:07:10 · answer #4 · answered by gebobs 6 · 0⤊ 0⤋
The answer is 8.
4(11 + x ) = 68 + x
x = 8
2007-07-17 07:04:09 · answer #5 · answered by e_kueh 2 · 1⤊ 0⤋
In 8 years...
2007-07-17 07:07:58 · answer #6 · answered by X 2 · 0⤊ 0⤋