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2007-07-17 06:49:20 · 9 answers · asked by yuleydis77 1 in Science & Mathematics Mathematics

9 answers

- 5x > 10
0 > 10 + 5x
- 10 > 5x
x < - 2

2007-07-20 11:10:57 · answer #1 · answered by Como 7 · 1 0

X < -2

If you have to show the work:

-5x + 1 > 11
-1 -1
____________
-5x > 10
Divide -5 by both sides
Change the inequality sign

x < -2

2007-07-17 13:57:19 · answer #2 · answered by yo_ho_ho_pirates_life 1 · 2 0

Solving inequalities like this one is much like solving equations, but you have to remember to reverse the sense of your inequality when you multiply or divide by a negative number or you have your expressions switch sides.

In this case, you treat the first step (add -1 to both sides) just as you would with an equation:

-5x > 10

Then you would divide both sides by -5 to isolate x on the left. However, because you are dividing by a negative number, you must also reverse the sense of your inequality, making the > into a <. The final result becomes

x < -2

2007-07-17 14:10:36 · answer #3 · answered by devilsadvocate1728 6 · 0 0

x < -2

2007-07-17 13:54:16 · answer #4 · answered by Anonymous · 2 0

x<-2

2007-07-17 13:53:19 · answer #5 · answered by poohbear5312 1 · 2 0

-5x=11-1
-5x=10
x=-2
this is not a true statement.
but if you are solving for inequalities; <>=; than you have to change the equal sign; after you solve it:

x=-2
x<-2;
than the above statement would be true; but first you have to look at your lesson plan;
and see what they are asking from you;
you also have to check your answer in the above question:

so is -2; less than 11?

yes, so this is a true statement.

You also have to graph this inequality; to see which numbers do not make this statement true.

2007-07-17 15:09:47 · answer #6 · answered by allspiceglitter 3 · 0 0

-5x+1>11
-5x>10
-x>2
x<-2

2007-07-17 14:01:35 · answer #7 · answered by davidcjo5 4 · 0 0

-2

2007-07-17 13:52:07 · answer #8 · answered by Anonymous · 1 1

Negative 3, or a negative number greater than three.

2007-07-17 13:52:49 · answer #9 · answered by lmnop 6 · 0 1

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