English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I need to find the integral of: x / radical(3 - x^4) dx

Thanks!

2007-07-17 04:05:41 · 3 answers · asked by Anonymous in Science & Mathematics Mathematics

3 answers

put x^2=t.the expression wil bcom:
integral(dt/2(radical(3-t^2)
now u can use the normal identity

2007-07-17 04:09:55 · answer #1 · answered by aviral17 3 · 1 0

Just bring the denumenator to the numerator.

x (3-x^4) ^-1/2 dx
-1/2 x (3-x^4)^(-1/2 - 1) * 4x^3
4x^3 * -1/2x (3 - x^4)^-3/2

-2x^4 (3-x)^4^-3/2

2007-07-17 11:20:04 · answer #2 · answered by Tall Chick 2 · 0 0

I do not know how to do it, but found the answer with that link

2007-07-17 11:12:54 · answer #3 · answered by maussy 7 · 0 0

fedest.com, questions and answers