= 3 (x² - 4x + 4)
= 3 (x - 2) (x - 2)
= 3(x - 2)²
2007-07-17 06:32:42
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answer #1
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answered by Como 7
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3x² - 12x +12
= 3(x² -4x + 4) It should be pretty obvious that there's a factor of 3 in all the numeric coefficients.
Note: (x² -4x + 4) looks like it might be perfect square… (a-b)²=a²-2ab+b²
Hint (x-2)… If you don’t know, you can always rely on the Quadratic Formula. But there are some “shapes” of polynomials you need to learn to recognize. If you do enough of them, you’ll learn them.
So
3x² - 12x +12 = 3(x² -4x + 4) = 3(x-2)²
CHECKING…
3(x-2)²=(3)(x-2)(x-2)
=[(3)(x) – (3)(2)](x-2)=(3x-6)(x-2)
=(3x-6)(x) – (3x-6)(2)
=(x)(3x-6) – (2)(3x-6)
=(x)(3x) – (x)(6) – (2)(3x) – (2)(-6) = 3x² -6x – 6x + 12
=3x² - 12x + 12…. See… It works.
2007-07-17 11:23:42
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answer #2
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answered by gugliamo00 7
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3(x^2-4+4) = 3(x-2)^2
2007-07-17 10:59:51
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answer #3
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answered by SS4 7
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3(x-2)^2
2007-07-17 12:06:32
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answer #4
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answered by xandyone 5
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Factor common term, 3, 3(x^2-4x+4)
Factor trinomial, 3(x-2)(x-2)
Simplify, 3(x-2)^2
2007-07-17 11:16:30
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answer #5
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answered by hrhbg 3
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3(x^2 - 4x + 4) = 3(x - 2)^2
2007-07-17 11:00:40
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answer #6
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answered by John V 6
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f(x) = 3 x^2 - 12 x + 12
f(x) = (3 x - 6 ) (x - 2 )
2007-07-17 11:03:01
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answer #7
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answered by anobium625 6
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3(x^2-4x-4)
=3(x-2)^2
2007-07-17 11:05:03
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answer #8
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answered by aviral17 3
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