as any processor is specified by its data register, does 8087 will be called as 80 bit processor
2007-07-16 19:55:31 · 5 answers · asked by Prof 1 in Computers & Internet ➔ Hardware ➔ Other - Hardware
The 8087 was the first math coprocessor for 16 bit processors designed by Intel.
2007-07-16 20:05:00 · answer #1 · answered by Frank S 2 · 0⤊ 0⤋
acklan is correct. 8087 is not considered a CPU, as it does function by itself. It only works alongside a mainboard designed for an 8086/8088 WITH a 8087 socket as well. It is considered only as a coprocessor. Thus, the normal definitions for a CPU does NOT apply.
In fact, if you read the info on Wikipedia, you'll see that 8087 does NOT have registers, but more like, well, stacks. ST0 to ST7.
2007-07-17 04:19:08 · answer #2 · answered by Kasey C 7 · 0⤊ 0⤋
I know that the 8086, 8087 and 8088 processors were all 16 bit processors. The Intel 80386 (aka 386) was the first 32 bit processor.
2007-07-17 03:01:48 · answer #3 · answered by Michael M 6 · 0⤊ 1⤋
That in not a processor. It was a math co-processor.
8086=8bit
20186=16bit
20286=16bit
20386=16bit
20486=32bit
Pentium=32bit
2007-07-17 02:59:54 · answer #4 · answered by acklan 6 · 1⤊ 0⤋
No, the 8087 is a 16bit processor. The name has nothing to do with how many bits it is.
2007-07-17 02:58:59 · answer #5 · answered by PoohBearPenguin 7 · 0⤊ 1⤋