Potassium carbonate reacting with aluminum chloride. (give reaction type & balance equation)?

Answer 1

All the above have failed to give the correct products, which are an aluminium hydroxide precipitate and carbon dioxide gas. Aluminium carbonate does not exist.

3K2CO3 + 2AlCl3 + 3H2O -----> 2Al(OH)3 + 3CO2 + 6KCl

Answer 2

K2CO3 (aq) + AlCl3 (aq) -> Al2(CO3)3 (s) + KCl (aq)

Basic equation, balanced charges within the molecules but the molecules are still unbalanced.

Step 1 to balancing an equation is to assume a known quantity of the most complicated molecular species. In this case, we assume 1 unit of Al2(CO3)3 is produced.

Step 2: Balance atomic and ionic species with one reactant and one product on each side, beginning with any found in step 1. This means balancing the Al and the CO3. Two Al come out, so two Al must have gone in. Similarly, 3 CO3 came out so 3CO3 must have gone in. This gives the equation so far of:

3 K2CO3 (aq) + 2 AlCl3 (aq) -> (1) Al2(CO3)3 (s) + ? KCl (aq)

Three of our four molecular species are now balanced and the remaining one is easy: 6 K went in and 6 Cl went in, so 6 K and 6 Cl must come out. This gives us the equation of

3 K2CO3 (aq) + 2 AlCl3 (aq) -> (1) Al2(CO3)3 (s) + 6 KCl (aq)

We don't need step 3, where we balance one to many and many to one, or step 4, in which we balance the remaining species, using simultaneous linear equations if necessary.

We proceed to step 5, where we check for any fractional molecules, of which there are none, and for a common factor in our coefficients. There is no common factor greater than 1 in the coefficients 1, 2, 3 and 6, so we need no scaling changes in our equation. We are now done.

This is what we call a double substitution reaction, in which the species do an ionic dance step in which they switch partners, so to speak.

Answer 3

K2CO3 + AlCl3 ----> Al2(CO3)3 + KCl

this reaction is double decomposition as it is producing an insoluble salt,aluminium carbonate by using two aqueos solutions.

Answer 4

This is the balanced eqn: 3K2CO3 + 2AlCl3 -> Al2(CO3)3 + 6KCl

Answer 5

1. 2K(s) + 2H2O(l) ----> 2KOH(aq) + H2(g) 3. C8H18(l) + O2(g) ----> 8CO2(g) + 9H2O(g) [Assuming complete combustion] 6. 3NaClO(aq) -----> 2NaCl(aq) + NaClO3(aq) Also (s) - solid (l) - liquid (g) - gaseous (aq) - aqueous (usually meaning dissolved in water)