The area of square A is 10 times the area of square B. What's the ratio of perim of square A to perim of squ B

Answer 1

Square A - a*a ---- area = a^2
Square B has an area of a^2/10
Each side = a/sqrt(10)

Perimeter of A ----- 4a
Perimeter of B ----- 4a/sqrt(10)

The ratio of the perimeters is sqrt(10):1

Answer 2

2 to 5

Answer 3

A rea of a square = l^2 where l is the length of each side. Perimeter of the square = 4l

lA^2 = 10 lB^2 where lA and lB are the lengths of sides of squares A and B respectively.

So, lA = sqrt.10 lB

Perimeter of A = 4 sqrt10 lB

= sqrt10 Peimeter B

So, the ratio is sqrt.10 : 1

Answer 4

Let the area of squareB be b^2 and that of square A be a^2
Hence a^2/b^2=10/1
square rooting both sides,we get
a/b=sqrt10/1
or,a:b=sqrt 10:1
As the perimeter of a square is four times its sides,the perimeter would also be in the ratio of sqrt 10:1