integral of cos^2 x/1-sin x dx?

0 ⤊

integral of cos^2 x/1-sin x dx?

2007-07-16 16:55:10 · 2 answers · asked by marvin_jimenez9 1 in Science & Mathematics ➔ Mathematics

2 answers

[cos^2(x)] / [1 - sin(x)]
= [1 - sin^2(x)] / [1 - sin(x)]
= [(1 - sin(x))(1 + sin(x))] / [1 - sin(x)]
= 1 + sin(x)

∫ [(1 + sin(x)) dx]
= x - cos(x) + C

2007-07-16 16:58:40 · answer #1 · answered by whitesox09 7 · 0⤊ 0⤋

I = â« (1 - sin Â² x) / (1 - sinx ) dx
I = â« (1 - sin x) ( 1 + sin x) / (1 - sin x) dx
I = â« (1 + sin x) dx
I = x - cos x + C

2007-07-20 02:17:05 · answer #2 · answered by Como 7 · 0⤊ 0⤋