help please?

Question

A 1.50 g lead bullet at 30.0°C is fired at a speed of 260 m/s into a large block of ice at 0°C, in which it embeds itself. What quantity of ice melts?

Answer 1

You have:

The heat from the bullet itself at 30C

The heat from the bullet's kinetic energy, (1/2)mv^2

The specific heat of lead is .13J/(Cg)

The heat from the bullet is then .13(1.5)30J

The heat from the kinetic energy is (1/2)(.0015)(260)^2J

The latent heat of fusion of ice/water is 334J/g

Total we have [(1/2)(.0015)(260)^2 + .13(1.5)30]J =57J

57J/(334J/g) = 171 milligrams