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Two marbles are drawn from a bag containing 6 white, 4 red, and 6 green marbles. Find the Porbility of both marbles being white.

2007-07-16 16:00:25 · 5 answers · asked by °†¿ÐámñéÐ?†° 2 in Science & Mathematics Mathematics

5 answers

Probability of Both White = ( 6 / 16) * (5/ 15) = 0.125

if you take and put all the marbles in one bag these are your chances of getting a white one however your chances of getting a red one is just a tad bit slimmer then the green or the white.

The probability of getting a green one is the same as the white because there are just as many green ones as there are white!

Hope this helps you with your question!

2007-07-16 16:16:38 · answer #1 · answered by Anonymous · 0 0

Assuming the marbles are drawn without replacement:
P(1st marble white) = 6/16
... and since a white marble has been removed,
P(2nd marble white) = 5/15

Hence, P(first two marbles are white) = (6/16) * (5/15) = (1/8)

Hope that helps!

2007-07-16 23:05:59 · answer #2 · answered by Bramblyspam 7 · 0 0

The total number of marbles would be 16.

fist time it would be 6/16;

It would be assumed that the first marble would be white. Therefore the odds of the second one being white would be 5/15.
total odds;

6/16 * 5/15 = 30 / 240

This reduces to one in eight chance.

2007-07-16 23:13:29 · answer #3 · answered by eric l 6 · 0 0

6white + 4red + 6green = 16 marbles

Probability of both being white (6/16) x (5/16) = 0.125

since you pick 1/6 marbles the first time making total white marbles = 5.

2007-07-16 23:05:50 · answer #4 · answered by Anonymous · 0 0

P (Both White) = ( 6 / 16) * (5/ 15) = 0.125

2007-07-16 23:03:17 · answer #5 · answered by Jeƒƒ Lebowski 6 · 0 0

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