English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

For the decomposition of NaHCO3, estimate the temperature at which the total pressure of the gases above the solids is 1 atm.

2NaHCO3 (s) <--> Na2CO3(s) + H2O(g) + CO2(g)

Additional Details
5 hours ago
Answer is 393 K.

If possible, please show work.
35 minutes ago
We'd need enthalpies of formation and standard entropies for those substances. And are you sure it's the total pressure is 1 atm or the partial pressure of each gas?

The question is the exact wording of the book.

NaHCO3 (s)
dHf* = -950.8 kJ mol^-1
dGf* = -851 kJ mol^-1
S* = 102 J mol^-1 K^-1

Na2CO3 (s)
dHf* = -1131 kJ mol^-1
dGf* = -1044 kJ mol^-1
S* = 135.0 J^-1 mol^-1 K^-1

H20 (g)
dHf* = -241.8 kJ mol^-1
dGf* = -228.6 kJ mol^-1
S* = 188.7 J mol^-1 K^-1

CO2(g)
dHf* = -393.5 kJ mol^-1
dGf* = -394.4 kJ mol^-1
S* = 213.6 J mol^-1 K^-1

2007-07-16 15:56:39 · 1 answers · asked by Anonymous in Science & Mathematics Chemistry

1 answers

Who needs that much ??????? Just find out heat of the reaction and then use

del G = del H - T del S

2007-07-17 06:00:52 · answer #1 · answered by ag_iitkgp 7 · 0 0

fedest.com, questions and answers