reduce if possible: (p^2 + 5p + 6)/(p^2 + 2p - 3)?

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2007-07-16 13:15:03 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics

First, factor, then see what they have in common.

(p^2 + 5p + 6)/(p^2 + 2p - 3)
= (p+3)(p+2)/(p-1)(p+3)
=(p+2)/(p-1)

2007-07-16 13:17:56 · answer #1 · answered by math guy 6 · 0⤊ 0⤋

(p^2 + 5p + 6) / (p^2 + 2p - 3)
= [(p + 3)(p + 2)] / [(p + 3)(p - 1)]
= (p + 2) / (p - 1)

2007-07-16 20:20:03 · answer #2 · answered by Francisco R 1 · 0⤊ 0⤋

(p+3)(p+2)/[(p+3)(p-1)]=

(p+2)/(p-1)

2007-07-16 20:21:11 · answer #3 · answered by 037 G 6 · 0⤊ 0⤋

Factor the top and bottom:
(p+2)(p+3)
---------------
(p-1)(p+3)

And then cancel:
p+2
-----
p-1

2007-07-16 20:20:09 · answer #4 · answered by Kevin B 2 · 0⤊ 0⤋