the confusion lies in using the term "weight." In common use, "weight" is used to refer to kilograms or pounds. In physics, kilograms or pounds are actually more accurately defined as _mass_. Weight refers to the _force_ caused by gravity, e.g. mass x (gravitational acceleration).
So yes, the _mass_ of a cubic meter of water on the moon is exactly the same as anywhere else--1000 kg. Therefore, its density, which is mass / volume, is still 1000 kg / m^3.
On the other hand, its _weight_ is approximately 1/6 of that on earth. Its weight on earth is
1000 kg x 9.8 m/sec^2
= 9800 kg x m / sec^2
= 9800 Newtons
Its weight on the moon is 1/6 of this, or about 1630 N.
2007-07-16 13:08:42
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answer #1
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answered by Anonymous
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There is about 1/6 the gravity on the moon as there is on Earth. Density of a liquid with a constant volume, varies according to the weight. The higher the weight, the higher the density. So the lower the weight the lower the density. The density would still be 1g/cc but it would only feel like a 6th of that.
2007-07-16 12:56:44
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answer #2
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answered by Lady Geologist 7
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The matter have their mass every where, and it doesn't change (unless the matter speed is near the light speed). The weight is a force F=g*m where g is the gravity acceleration. In the Earth, the weight of a pond (of matter) is a pound (of weight).
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Density is the ratio of mass and volume
d=m/V
As the mass is the same, the volume defines the density.
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The Volume changes with pressure and temperature.
In the Moon the pressure is zero, so the water will boil and escape to the space. But if the water is in a bottle (closed), their density would be near 1000 kg/m^3 (if the temperature is near 40 F)
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Moon's gravity = 1/6 Earth's gravity
2007-07-16 14:18:52
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answer #3
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answered by Anonymous
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In physics, "density" is defined as "mass per unit volume", not as "weight per unit volume". A kilogram is a unit of mass, not weight. Moving an object into a different gravity field changes its weight, but not its mass. Therefore, the density of water is the same on Earth or on the moon.
In high school, "density" is defined as "stupidity; slow-wittedness; obtuseness", not as "the ability to sink and drown in a wading pool". People who think a pound is a unit of mass are dense enough to drown in the Dead Sea.
A balance measures mass, not weight. You put an unknown mass on one pan and balance it with a known mass on the other pan. You'll get the same result on Earth or on the moon. A spring scale, on the other hand, measures weight. It will measure 1/6 as much on the moon.
2007-07-16 13:57:22
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answer #4
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answered by Anonymous
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So, I'm thinking that your question has been answered. Density is effected by temperature, with 1000kg/m3 being at 4*C.
Since specific weight is dependent on gravity, it will be different on the moon.
2007-07-16 15:13:26
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answer #5
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answered by bedbye 6
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Like Jay W said, it's still the same amount of water, in the same volume, therefore the same density. On the other hand, if the water is in a OPEN container, it would lose heat very fast. The top layer of water would boil away in the vacuum, taking heat away with it. The rest of the water would freeze solid.
2007-07-16 13:51:46
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answer #6
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answered by morningfoxnorth 6
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Nope, the Moon's 1/6 G changes the weight of a cubic meter of mass. So the density on the Moon is different
2007-07-16 13:02:01
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answer #7
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answered by Anonymous
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Mass doesn't change ...since density = mass /volume,
density remains the same on the moon even though the total weight (due to gravity) changes.
2007-07-16 15:00:31
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answer #8
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answered by Anonymous
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the density of a substance is constant. even though, the earth's mass is 81.36 times the mass of the moon, when you take into account that the earth's radius is 3.67^2 times the moon's radius, that makes earth's surface gravity 6 times more than the moon's.
2007-07-16 13:27:21
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answer #9
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answered by ftm821 2
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Convert inches to metric, calculate the volume, multiply by the density, keep your decimal point in the right place, and Robert is your parental sibling.
2016-05-19 21:33:54
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answer #10
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answered by ? 3
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