A baseball team has played 12 games and has won 83 1/3 % of them. It has 16 remaining games on the schedule.?

Question

If it should win 62 1/2 % of the game to be played, what would be its standing at the close of the season.

Answer 1

Hello

83 1/3 % * 12 = 10 and 621/2% * 16 = 10 so they would win 20 out of 28 or 20/28 = 71.43%

Hope This Helps!

Answer 2

(12 x 83 1/3) / 100 = 10, so your record is 10-2 so far

(16 x 62 1/2) / 100 = 10, so your record is 10-6 over the remaining games.

Your total record will be 20-8

Answer 3

20 wins, 8 losses.

83 1/3% of 12 = 12 x .8333 = 10
62 1-/2% of 16 = 10 x .625 = 10

therefore 20 wins.

total games = 12 + 16 = 28.

28 - 20 = 8

therefore, 8 losses.