What are two consecutive integers such that twice the smaller decreased by the larger equals -67?

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2007-07-16 11:02:37 · 4 answers · asked by Tman # 4 1 in Science & Mathematics ➔ Mathematics

Let hte nos. be x and x+1

2x - (x+1) = -67
x = -66
x+1 = -65

2007-07-16 11:09:46 · answer #1 · answered by Dr D 7 · 0⤊ 0⤋

Hello

Let x = smallest number then
x+1 = largest so we have

2x -(x+1) = -67 so x -1 = -67 or x = -66 and x+1 = -65

Hope This Helps!!

2007-07-16 18:09:31 · answer #2 · answered by CipherMan 5 · 0⤊ 0⤋

two consecutive integers n and n+1

then 2*n - (n+1) = -67 => n-1 = -67

n = -66

so your integers are -66 and -65

2007-07-16 18:08:00 · answer #3 · answered by Anonymous · 0⤊ 0⤋

-66,-65

2x-(x+1)=-67 solve for x

2007-07-16 18:12:26 · answer #4 · answered by College Guy 2 · 0⤊ 0⤋