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F(x)=3x+2/ x^2-4x+4

2007-07-16 08:12:10 · 5 answers · asked by Anonymous in Science & Mathematics Mathematics

5 answers

Since division by zero is undefined, the domain excludes those values.
Set the denominator equal to zero & solve:
x^2 - 4x + 4 = 0
(x - 2)(x - 2) = 0
x = 2.
The domain is all Real numbers, except 2.

2007-07-16 08:17:33 · answer #1 · answered by S. B. 6 · 1 0

if u first factorize the denominator u will get (x-2)^2.
now, f(x)=3x+2/(x-2)^2

domain is the set of those values for which f(x) is always real.we can't inculde those values of x in the domain for which f(x) becomes imaginary or infinity.
here, if we set x=2 then the denominator becomes 0 and thus f(x) becomes infinity. so the domain of f(x) will be all real numbers except 2.
domain f = R- {2}; where R is the set of real numbers.

2007-07-16 15:20:28 · answer #2 · answered by taukir_imam 1 · 1 0

whatever the value of x that makes the expression on the denominator equals to 0 is the restriction or domian.

x^2 - 4x + 4 = 0
(x - 2)^2 = 0
x = 2

so, x can be any real numbers, except 2

2007-07-16 15:15:50 · answer #3 · answered by      7 · 2 0

The denominator can be factored as (x-2)^2.

The domain is all real numbers excluding 2.

2007-07-16 15:19:31 · answer #4 · answered by gebobs 6 · 1 0

The domain just means what values of X are allowed.

In this case, you can use any x except x=0. So the domain is - infinity to + infinity, excluding zero.

2007-07-16 15:15:10 · answer #5 · answered by mikeburns55 5 · 0 2

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