7a^3-28a.. need some help simplifing this thanks
2007-07-16 07:58:51 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Factoring; 7a( a^2 - 4) = 7a (a-2) (a+2)
2007-07-16 08:06:54 · answer #1 · answered by ? 5 · 0⤊ 0⤋
the answer is 7a( a+2)(a-2)
reason: you must factor by taking out 7a from both the 7a^3 and the 28a. When this is done you leave a^2 and 4 in the parentheses
7a(a^2-4)
now you look and see that 4 in the parentheses is 2 times 2 so you realize that this is a product of two squares.
7a(a+2)(a-2)
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vote me as best answer!
2007-07-16 08:02:46 · answer #2 · answered by Anonymous · 0⤊ 2⤋
The most obvious suggestion is 7a(a^2-4) which can be expressed alternatively as 7a(a-2)(a+2) You can choose which of these you find simpler.
Bramble
2007-07-16 08:08:29 · answer #3 · answered by Bramble 7 · 0⤊ 0⤋
Factor out a 7a, and get
7a*(a^2-4)
(a^2 - 4) factors as
(a+2)(a-2),
so the simplified answer is
7a(a+2)(a-2)
2007-07-16 08:03:01 · answer #4 · answered by Not Eddie Money 3 · 0⤊ 0⤋
factor out "7a" out of the two terms and you are left with....
7a(a^2-4)
the resulting bracket is a Difference of Squares Factor....
Therefore the final answer should be....
7a(a+2)(a-2)
2007-07-16 08:04:59 · answer #5 · answered by A G 1 · 0⤊ 0⤋
Factor:
7a(a^2 - 4)
7a(a - 2)(a + 2)
2007-07-16 08:03:23 · answer #6 · answered by yeeeehaw 5 · 0⤊ 0⤋
7a(a² - 4) = 7a (a - 2) (a + 2)
2007-07-17 06:13:49 · answer #7 · answered by Como 7 · 0⤊ 0⤋
7a^3-28a
=7a(a^2-4)
=7a(a-2)(a+2)
2007-07-16 08:03:52 · answer #8 · answered by fofo m 3 · 0⤊ 0⤋
7a(a^2-4)
7a(a-2)(a+2) ans
2007-07-16 09:16:15 · answer #9 · answered by MAHAANIM07 4 · 0⤊ 0⤋
7a(a^2-4)
7a(a-2)(a+2)
2007-07-16 08:12:52 · answer #10 · answered by Dave aka Spider Monkey 7 · 0⤊ 0⤋