50 g of sugar (C12H22O11)is dissolved in 500g water at standard pressure. How much is the boiling point raised

Answer 1

Delta T = Kb x m
m = moles solute / Kg solvent
Molecular weight = 342 g/mol
50 g / 342 = 0.146 moles
m = 0.146 / 0.500 Kg = 0.292
delta T = 0.512 x 0.292 = 0.150 °C
The boiling point will be 100 + 0.150 = 100.150 °C

Answer 2

Data required.