Rate Law???

Question

Which of these rates would you expect to have the largest value? Why?
Initial Rate, Average Rate and Instantaneous Rate

Answer 1

Initial rate, because at the start of any reaction the concentration of all reactants is at their highest values.

Answer 2

Gervald is correct, and I have no idea why someone gave him a thumbs down on his answer. The rates of most reactions have some dependence on the concentration of reactants. Thus, at the very beginning of the reaction when all reactant concentrations have their highest values is when you will measure the highest rate. The only time this isn't true is for zeroth order reactions.

In contrast, an average rate, or an instantaneous rate (at a time other than t=0) will include times when the rate is lower because some reactant has already reacted.

Answer 3

Tripling the ClO2 concentration from 0.020 to 0.060 motives the cost to extend via 0.0248/0.00276 = 9.0 cases, collectively as protecting [OH-] consistent. R is proportional to [ClO2]^n 9R is propotional to [3ClO2]^n, so n = 2 because of the fact 3^2 = 9. the cost is 2d order with appreciate to [ClO2] Tripling OH- from 0.030 to 0.090 motives the cost to extend via 0.00828/0.00276 = 3, collectively as protecting [ClO2] consistent. R is proportional to [OH-]^m 3R is proportional to [3OH-]^m, so m = a million because of the fact 3^a million = 3. the cost is first order with appreciate to [OH-] . the cost regulation is R = ok[ClO2]^2[OH-]^a million using trial a million documents: ok = R / {[ClO2]^2[OH-]} = 0.0248 / {(0.060)^2(0.030)^a million} = 230 a million/M^2 R = 230 a million/s M^2 x (0.one hundred)^2 x (0.030)^a million = 0.069 M/s