I need help with some math problems, I am hopeless..?

Question

1) Solve the system, using substitution. Write the solution as an ordered pair leaving no spaces, or write no solution or infinitely many. Example: (2,1)
x = 2y - 2 and 3x - y = 14


2) Solve the system, using substitution. Write the solution as an ordered pair leaving no spaces, or write no solution or infinitely many. Example: (2,1)
2m - 3n = 6 and m = 3 - 2n


3) Solve the system, using substitution. Write the solution as an ordered pair leaving no spaces, or write no solution or infinitely many. Example: (2,1)
2m - 3n = 6 and m = 3 - 2n


4) Solve the system, using substitution. Write the solution as an ordered pair leaving no spaces or write no solution or infinitely many solutions Example: (2,1)
4x + y = 4 and y = 4 - 4x


5) Solve the system, using substitution. Write the solution as an ordered pair leaving no spaces, or write no solution or infinitely many solutions; Example: (2,1)
x = 4y and 2x + 3y = 44

Please help me...

Answer 1

x = 2y - 2
3x - y = 14
3(2y-2) - y =14 (substituting #1 into #2)
6y - 6 - y =14
5y = 20
(6,4)

2m - 3n = 6
m = 3 - 2n
2(3-2n) - 3n = 6 (substituting #2 into #1)
6 - 4n -3n = 6
7n = 0
(3,0)

I believe problems 2 and 3 are the same.

4x + y = 4
y = 4 - 4x
The equations are identical...one equation, two unknowns...infinite solutions

x = 4y
2x + 3y = 44
2(4y) + 3y = 44 (substituting #1 into #2)
11y = 44
(16,4)