2007-07-16 02:38:56 · 8 answers · asked by bee 1 in Science & Mathematics ➔ Mathematics
x² - 7x + 10 = 0
x² - 2x - 5x + 10 = 0
x(x - 2) - 5(x - 2) = 0
(x - 5)(x - 2) = 0
- - - - - - - - -s-
2007-07-16 04:25:53 · answer #1 · answered by SAMUEL D 7 · 1⤊ 0⤋
x^2 - 7x + 10
(x - 2 ) (x - 5 )
2007-07-16 09:43:48 · answer #2 · answered by CPUcate 6 · 0⤊ 0⤋
x^2-7x+10
=>x^2 - 2x - 5x + 10
=>x(x-2) - 5(x-2)
=>(x-5)(x-2)
2007-07-16 09:43:49 · answer #3 · answered by sushant 3 · 0⤊ 0⤋
x^2-7x+10 = (x-5)(x-2)
2007-07-16 09:41:43 · answer #4 · answered by Anonymous · 0⤊ 0⤋
(x - 5) (x - 2)
Check
x (x - 2) - 5 (x - 2)
x² - 2x - 5x + 10
x² - 7x + 10 as required
2007-07-16 14:07:59 · answer #5 · answered by Como 7 · 0⤊ 1⤋
Hey there!
Here's the answer.
x^2-7x+10 -->
x^2-5x-2x+10 -->
x(x-5)-2(x-5) -->
(x-2)(x-5)
So the answer is (x-2)(x-5).
Hope it helps!
2007-07-16 10:30:22 · answer #6 · answered by ? 6 · 0⤊ 0⤋
first you look at the problem, and ask yourself, what adds up to -7 and multiplies to +10?
the answers would be -2 and -5
(before that or after if you decide, you should divide the x squared and put into two separate parenthesis)
so the correct answer for this problem would be (x-5) (x-2)
hoped this helped â¥
2007-07-16 09:46:22 · answer #7 · answered by Footballfan2345 2 · 1⤊ 0⤋
(x-5)(x-2)
2007-07-16 09:42:11 · answer #8 · answered by Adam M 1 · 0⤊ 0⤋